Motion in a Straight Line
Class 11 · Motion in a Straight Line
Velocity–Time Graph
Linear v(t) from constant acceleration — area under curve = displacement.
Key Notes
01
v-t graph: slope = acceleration; area under the curve = displacement.
02
For uniform acceleration, v-t is a straight line: v(t) = v₀ + at.
03
A v-t line crossing zero means the object reversed direction.
04
Positive area = forward displacement; negative area = backward displacement.
Formulas
Velocity with uniform a
First kinematic equation.
Displacement from area
Area under v-t curve.
Important Points
Area above the t-axis and below subtract — only signed area gives net displacement.
Total distance = sum of |areas| regardless of sign.
Velocity–Time Graph notes from sciphylab (also known as SciPhy, SciPhy Lab, SciPhy Labs, Physics Lab). Class 11 physics revision for JEE Mains, JEE Advanced, NEET UG, AP Physics 1/2/C, SAT, and CUET-UG.